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Digital Designs M4 and Z1 protection "issues"


AmmoJammo

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So why is it that more batteries/more charge results in the amps going in to protect more?

that's what the question has been the whole time, and no one has been able to answer it.... amusing responses, but very uninformative.

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I know nothing about an amps internals, but what I gathered from this thread: A amplifier is set to make X power.

If you go over X amount of power it will go into protect.

If you have more voltage going to the amplifier(less voltage drop), the amp will produce more. Putting it over that X amount, putting it into protect.

If you have less voltage going to the amplifier(more voltage drop), it won't be reaching that X amount, not going into protect.

Am I correct or am I off?

The thing is though, that's what I would have assumed, but I haven't even been able to get the same SPL from the amp with the more stable supply voltage, as its simply more prone to protect.

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The amp circuit is powered off the power supply in the amp, the more voltage you have on that circuit the faster the response time. So my guess is you are dropping so low of voltage that your amp protection circuit is slowing down to the point it isn't catching the impedance change OR your amp isn't making enough power on the current output stage to trip the amp into protect. When you add more voltage you allowing the amp to function as designed and it protecting itself.

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my best guess....OP is trolling HARD. From the information he has stated, he knows more than average about his setup and just jogging around the answer. Surprised this thread has reached 5 pages.

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im sure someone else is more qualified to answer this.

its really hard on the amp as it trys to put out the same power so as the voltage drops the amps its consuming goes up combine that with low impedance and its just bad news

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Any time you have have a power wire next to your frame put some rubber hosing (or cut up an innertube) around it. The wire is bound to wiggle (due to driving or flex) and the casing will eventually wear through.

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but when the input voltage drops, the voltage rails drop, so the output voltage drops, which means so does the current....

it won't just draw more current to try and output the same voltage...

if you know everything why do you ask???

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