ok, nevermind my entry... now i get it... its just fun and adding up some numbers... sorry
how should that work?
i mean... its maximal fuse of 40 amperes...
on a normal voltage at (optimistic) 14,8 Volts and a efficiency at 100 % (very optimistic)
there are 14,8 volts * 40 amperes = 592 Watts...
these fuses are lazy... that means for 2 -3 secs they can handle 20 % more...
40 amperes * 1,2 = 48 amperes for 3 secs
14,8 volts * 48 amperes = 710,4 watts
thats physical the maximum. and a efficiency at 100 % is not given... on 0,5 ohm perhaps 60 or 70 %
that means
710,4 watts * 0,7 = 497,8 watts...
thats my assumption.
but im interested... and im looking forward for the results
greets
olly