tweeters in series??

[andrew018018]

Well i have 2 set of JBL tweeters that are 4 ohms each, and i have a bipolar crossover capacitor which handles quite a decent amount of power, can i wire both tweeters in series and then to one capacitor per pair?

like:

(+)---------------------(tweeter)-----------(tweeter)-----------(capacitor)-----------------(-)

[andrew018018]

just a note, they will be in parallel with two 6.5" 8ohm mid-range drivers

[andrew018018]

possibly no-one knows?

[Shankkilla420]

I dunno about the cap but why would you wire it into the speaker wire? Wouldn't it go inline with your amps power wire?

[White Lightning]

You have 2 component sets ... why don't you use the passive crossovers that came with them ... then series the complete sets to a 8 ohm load for the 2 channel amp ???

or ... what final ohm load do you want the amp to see ??

[andrew018018]

You have 2 component sets ... why don't you use the passive crossovers that came with them ... then series the complete sets to a 8 ohm load for the 2 channel amp ???

or ... what final ohm load do you want the amp to see ??

My idea was to have a 2.6ohm load(actually it should end up being a bit less) on each of the front 2 channels of my 4channel so that i'll get about 80 watts a side,

that's the reason that i want the tweeters in series, i'm certain that the cap to will take the power and theoretically the circuit makes sense...

but i just want some advice from some experienced people

thank you for your reply

[andrew018018]

I dunno about the cap but why would you wire it into the speaker wire? Wouldn't it go inline with your amps power wire?

Capacitors inline with tweeter are used as highpass filters, they cut off at a certain frequency according to their capacitance

[Shankkilla420]

Why such a funky load after all is said and done?

[andrew018018]

Why such a funky load after all is said and done?

Funky load? A load doesn't have to be a whole number or 1, 2 or 4 ohm.. as with the case of most 4channels is that they put out the most power at 2 ohms per channel, so i wanted to get as close as possible

This is how parallel impedance is worked out:

1/Rtotal = 1/Rmid1 + 1/Rmid2 + 1/(Rtweet1 + Rtweet2)

Rtotal = 1/ (1/8 + 1/8 + 1/(4+4) )= 2.66* ohm

[Shankkilla420]

Why such a funky load after all is said and done?

Funky load? A load doesn't have to be a whole number or 1, 2 or 4 ohm.. as with the case of most 4channels is that they put out the most power at 2 ohms per channel, so i wanted to get as close as possible

This is how parallel impedance is worked out:

1/Rtotal = 1/Rmid1 + 1/Rmid2 + 1/(Rtweet1 + Rtweet2)

Rtotal = 1/ (1/8 + 1/8 + 1/(4+4) )= 2.66* ohm

Ohh wow I feel dumb, well sounds like you should go for it tbh.