Enough power?

[MIKE-2U]

So i am strengthing my electrical system and need some knowledge. I have an aq 3500.1 at .5 ohms. I am picking up a d3400 under my hood tonight. I also have a singer 250 alt and all 1/0. I know i need battery (s) in back but how many and which size. Also whats the equations to figure out how big alt you need and how much battery amps you need ?

[Born_Again]

http://www.supercirc...-Amps-Converter

Edit: Is this what you're looking for? 12v x 250 amps = 3000 watts?

Edited July 10, 2012 by Born_Again

[MIKE-2U]

Lookig to see if i have enoygh alternator power and how muh battery power i need. I kniw HHR Ed has some equations not sure im mobile now so ill look when i get home

[Watch the bass]

The only enough power is add a batt in the trunk, for a lean budget maby one of those http://www.stevemeadedesigns.com/board/topic/144556-dont-seem-like-a-bad-deal/

[Born_Again]

http://www.supercirc...-Amps-Converter

Edit: Is this what you're looking for? 12v x 250 amps = 3000 watts?

500 watts are left over. We need to divide that by 12 volts and that will give us about 42 amps.

If you have, lets say, an XS D3100 battery that has an amp hour rating of 110, your battery will

last about two and a half hours, in theory. The harder you run your batteries, the less you'll see

in a real life application. If you have a 110 amp hour battery, and you're pulling 5 amps from it, you'll

probably see 110 amp hours from the battery. If you're pulling 90 amps from a 110 amp battery, you won't

get over an hour of time, because it's being pushed so hard. It might only give you half an hour of time.

I have a thread in the XS power forum asking for these exact numbers for a D3100 but I'm still waiting for an

answer, after 5 days. I'm just a newb, so someone please correct me if I'm wrong.

OP, I'm only figuring in 3500 watts of power for your amp (I don't even really know what it's putting out).

EDIT: To clarify amp hours

Edited July 11, 2012 by Born_Again

[ch0sen]

you need to know how efficient that aq is at .5 ohm

14volts x 250 amps = 3500 watts

but that aq is prb only 50-60 % efficient at .5 ohm so your back down to around 1800 watts

so 1800 watts / 12 volts, since your alt isn't keeping up we will say 12, plus its always better to have extra

so 1800/12=150 amps you need to make up with batteries

[ch0sen]

more or less

watts=volts x amps

Amp efficiency means how many of those amps the amp can actually turn into watts

[Born_Again]

you need to know how efficient that aq is at .5 ohm

14volts x 250 amps = 3500 watts

but that aq is prb only 50-60 % efficient at .5 ohm so your back down to around 1800 watts

so 1800 watts / 12 volts, since your alt isn't keeping up we will say 12, plus its always better to have extra

so 1800/12=150 amps you need to make up with batteries

OK, you lost me. How is his alt not keeping up? His alt will provide 3000 watts.

[ch0sen]

but his amp doesn't see watts, it sees amps

and an amp has to work to turn those amps into watts

and no amp is 100% efficient and when you lower the ohm you lower your efficiency so if you work your way down to .5 ohm your really running inefficient

idk the efficiency of that aq amp but i'm sure its quite good, 50-60% is just a low number to keep his voltage up.

[Born_Again]

but his amp doesn't see watts, it sees amps

and an amp has to work to turn those amps into watts

and no amp is 100% efficient and when you lower the ohm you lower your efficiency so if you work your way down to .5 ohm your really running inefficient

idk the efficiency of that aq amp but i'm sure its quite good, 50-60% is just a low number to keep his voltage up.

OK, so the amp is pulling 3500 watts, but actually converting maybe 2000 watts of it?

But it's using 290 amps? Or is the inefficency making it pull only 180 or something amps?

Either way, I don't see how there is a loss of 100+ amps figuring in only this amp, or am I missing something?

I'm not arguing with you, I just want to understand. Thanks dude.