look over my box tuning/port area

[blownengine]

Are you using 3 as the hypotenus or one of the legs of the triangle?

And that box sounds good for 2 15's

Even if i did turn the subs around to normal would it still sound decent? trying to make it where it is sorta universal working both ways inverted and normal

Yea it would work either way. With them in normally your cubic feet would go down to around 6ish. Which is still ok.

[Winn]

Ok. The one day I dont bring home a calculator. Im roughyl doing these calculations.

A triangle with a hypotenuse of 3 will have legs with lengths of roughly 2.1 in. (Sin(45)*3)

So (.5*2.1)*2.1= roughly 2.205 for the area of that triangle.

So to find out how much area the 45 takes up multiply that number (2.205) and multiply it by how long the 45 piece will be.

OKay another challenge do the same for 4 1/2 inch hypotenuse and 2 1/4 inch height.

sorry i havent had geometry in a couple years i totally forgot.

Edited May 19, 2011 by Winn

[blownengine]

A right triangle with a hypotenuse of 4.5 actually has a height of 3.15.

The area of that triangle would be roughly 4.96.

EDIT: I think you are trying to take the wood thickness into account and are confusing yourself.

Edited May 19, 2011 by blownengine

[Winn]

A right triangle with a hypotenuse of 4.5 actually has a height of 3.15.

The area of that triangle would be roughly 4.96.

EDIT: I think you are trying to take the wood thickness into account and are confusing yourself.

how? because i drew it out on a piece of paper to actual size like it would be? although i dont have a protractor so idk if the angles are correct

so it will take up around .5 square inches per corner?

Yes i am.. I am measuring how much the whole thing will take up not just the actual closed air space

Edited May 19, 2011 by Winn

[blownengine]

A right triangle with a hypotenuse of 4.5 actually has a height of 3.15.

The area of that triangle would be roughly 4.96.

EDIT: I think you are trying to take the wood thickness into account and are confusing yourself.

how? because i drew it out on a piece of paper to actual size like it would be? although i dont have a protractor so idk if the angles are correct

so it will take up around .5 square inches per corner?

Yes i am.. I am measuring how much the whole thing will take up not just the actual closed air space

Sorry. You switched your numbers so I thought you might be getting confused.

[Winn]

A right triangle with a hypotenuse of 4.5 actually has a height of 3.15.

The area of that triangle would be roughly 4.96.

EDIT: I think you are trying to take the wood thickness into account and are confusing yourself.

how? because i drew it out on a piece of paper to actual size like it would be? although i dont have a protractor so idk if the angles are correct

so it will take up around .5 square inches per corner?

Yes i am.. I am measuring how much the whole thing will take up not just the actual closed air space

Sorry. You switched your numbers so I thought you might be getting confused.

okay so WITHOUT TAKING IN WOOD WIDTH. 3 inch hypotenuse and a 1.5 inch height i believe? how much space would that take up? Also did you times it by the height of my box? and when you times them together you have to minus the 3/4 inch of both of the wood top and bottom?

[blownengine]

Ok now I am getting confused. I just didnt know if you were using that length as the inside or outside of the 45.

[Winn]

Ok now I am getting confused. I just didnt know if you were using that length as the inside or outside of the 45.

do you think the box will be efficient or sound like total dog shit?

Edited May 19, 2011 by Winn

[Winn]

Bump for anyone elses opinion?

Opinions will be nice?

UPDATED: Only 1 common port wall so that is over with.

[blownengine]

Can you post a picture of Torres after you corrected the port walls so we can check it?