How do you figure ohm rise?

[lagexe]

google is being less than helpful:

http://www.google.com/#hl=en&sa=X&ei=1Hk0T-iUMc2Utwfl4_WnAg&ved=0CBkQvwUoAQ&q=how+to+figure+ohm+rise&spell=1&bav=on.2,or.r_gc.r_pw.,cf.osb&fp=f2900e4a30b61916&biw=1024&bih=650

So now, I'll ask here. What is the formula, or is there one?

[armykyle1]

there's no way to estimate rise, you have to use above to get a real number. No two setups are alike.

Port eff is king

[Nine8SST]

And even more importantly....what can you do about rise?

[lagexe]

Gotta measure a few things.

Get a clamp on AC Amperage meter, and a Digital Voltage meter.

Play a tone at your desired frequency and measure AC current out of the amp. At the same time measure AC voltage out of the amp.

Use a true RMS meter with peak hold.

Multiplying the 2 figures will give you power.

Dividing voltage by current will tell you impedance.

R=E/I

R is resistance, E is voltage, I is current. Its Ohm's law

I knew a little of this, I used to tinker around with breadboards. My more specific question is this:

If I have 2, 4, 8 DVC subs, and I wire them to a desired ohm, How would I get the ohm value (with ohm rise).

I understand that your method will tell me the current ohm value with ohm-rise, but is there a more generalized way?

Will 2 sub @ D1 wire to =1ohm, or 1.2ohm, or is there no general way to tell?

It was answered already, Thanks guys!

[Decaf]

ACV/ACA=rise

ACV*ACA=wattage