Brettward Posted September 27, 2012 Report Posted September 27, 2012 Alright guys, so I have been making multiple designs for boxes that could possibly fit in my Subi, and this one is a design for 1 15" AA Mayhem. I have looked over the Torres cut out part and the angled cutout doesnt make sense... the width is correct (if i wanted the angle between the sides and bottom) ANYWAYS take a look and tell me if this i something i am not catching or it is an error?
Brettward Posted September 27, 2012 Author Report Posted September 27, 2012 OMG so for some reason, it won't show my torres pic sooo maybe this wont work nevermind.. so another NOOB question, how the hell you post a pic?
WastedTalent Posted September 27, 2012 Report Posted September 27, 2012 upload to photobucket, click the link pic here, get the tag for the pic and put in the link thing... Or... you can upload to tinypic, it'll give you the "link for message boards"... copy and paste that in the link thing... cept delete the parts off both sides and it should work. Sheena = pedobear
revoracing247 Posted September 27, 2012 Report Posted September 27, 2012 no offence but this made me lol just out of curiosity how did you try adding photos? ~ If it was easy, everybody would be doing it ~
WastedTalent Posted September 27, 2012 Report Posted September 27, 2012 no offence but this made me lol just out of curiosity how did you try adding photos? Sheena = pedobear
Brettward Posted September 27, 2012 Author Report Posted September 27, 2012 HAha thanks... now the Forrum noob really stands out... and I tried dropping and dragging, it worked before i posted but then afterwards it just disapeared. ANYWAYS: torres photo Plus Design Photo to show how the hell it got the angled demensions... BOX DESIGN As you can see, either if i were to put the angled part between the top or bottom, the 16.35" i do not understand...
revoracing247 Posted September 27, 2012 Report Posted September 27, 2012 in torres im pretty sure hight, width are for square ports and the # of ports and diameter are for circle ports. so i don't think you need both. and it you know the height of the box and the angle can't you do simple trig and figure out the length? ~ If it was easy, everybody would be doing it ~
revoracing247 Posted September 27, 2012 Report Posted September 27, 2012 ok so i got off my lazy butt and pick up a pen and my calc. if the difference between the 2 depths is 6.5" and the height is 15" then a^2+b^2 = c^2 so 15^2 + 6.5^2 = c^2 so c = about 16.3477872" or sqr root of 267.25" and that is the outer length of the back piece edit: that's if the back piece goes from the very bottom to the very top ~ If it was easy, everybody would be doing it ~
Brettward Posted September 27, 2012 Author Report Posted September 27, 2012 Ahh yes, the only reason i put a diameter there was cuz i never took the 1 out of the number of ports. you are right about that. But yes i can just fig that out, i never did trig but, sure i can figure that out hahaha. I just wanted to know if the Angled part was an error or if it really was true.. Also wanna ask how you calculate the placement of the bracings?
Brettward Posted September 27, 2012 Author Report Posted September 27, 2012 Ahh interesting haha. man i need to get back in school... thanks for the help.. sucks that i dont have a good calculator.. or one at all
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