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How to calculate watts lost/gain from voltage variances


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Lets say an amp puts out 4000 watts at 13.8 volts. And it is only getting 12.5 volts. Or it gets 14.4 volts

All other variables are constant.

4000/13.8=290(about)

290 x 12.5 =3625

290 x 14.4 =4176

Does this math work?

Is there a general rule of thumb?

Does it vary amplifier to amplifier?

Is the loss of watts much higher or much lower based on voltage increase/decrease?

Is there even a way to find out without clamping or testing?

I am just curious, and maybe others are too.

Any ideas or experience with this would great to have input on.

Thank you

Edit: If this isn't the appropriate section for this mods please move it

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It's not that simple.

Efficiency of the amplifier could change at different supply voltages.

Also, at different power levels, load impedance may change which would in turn, change the power output.

Each amplifier and each application would have differences.

You can figure estimates based on best case scenarios like your math shows. But the only true way to know is to measure the output with meters or a power measuring device like the Amp Dyno

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It's not that simple.

Efficiency of the amplifier could change at different supply voltages.

Also, at different power levels, load impedance may change which would in turn, change the power output.

Each amplifier and each application would have differences.

You can figure estimates based on best case scenarios like your math shows. But the only true way to know is to measure the output with meters or a power measuring device like the Amp Dyno

It's not that simple.

Efficiency of the amplifier could change at different supply voltages.

Also, at different power levels, load impedance may change which would in turn, change the power output.

Each amplifier and each application would have differences.

You can figure estimates based on best case scenarios like your math shows. But the only true way to know is to measure the output with meters or a power measuring device like the Amp Dyno

Alright cool. This exactly the kind of answer I was looking for. Thank you

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