DLHgn Posted December 12, 2016 Report Posted December 12, 2016 Nope 2 3 x 3 ports = (3*3)+(3*3) = 18 1 6 x 6 port = (6*6) = 36
tedbear220 Posted December 12, 2016 Report Posted December 12, 2016 so a 3" aero will have and effective area of 7 square inches. of port, so 2 3" would be 14 square inches. 1 6" is 28 square iirc.
DLHgn Posted December 12, 2016 Report Posted December 12, 2016 It would be wrong if I was doing it for a 3" aero port or 6" aero port but he is talking about square ports so actually ^^that is wrong. He has a square port currently and is talking about modifying it
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