Need Help Please

[kjstoken360]

dynamicauto off of ebay

[kjstoken360]

If you cannot exchange the 4 ohm sub, sell it and buy another dual 2 ohm.

You can then wire properly and end up with a 2 ohm final load.

OMFG Now i have to sell my 4ohm sub that i bought earlier and get a 2 ohm sub just so i can get a 2ohm impedance for 2 of the subs

[kjstoken360]

FUCK MY LIFE

[kjstoken360]

If you cannot exchange the 4 ohm sub, sell it and buy another dual 2 ohm.

You can then wire properly and end up with a 2 ohm final load.

Thank you for making me realize i ordered the right sub, but the first time i didnt.

[bkolfo4]

With DVC 2 ohm, you series the coils on each sub making each sub 4 ohms. Then parallel the 2 subs to the amp making a final load of 2 ohms.

[kjstoken360]

With DVC 2 ohm, you series the coils on each sub making each sub 4 ohms. Then parallel the 2 subs to the amp making a final load of 2 ohms.

Yeah i finally figured that out. Also i figured out that to figure out the ohms you just do{ (ohm x ohm) / (ohm+ohm) }

So with the two 2 ohm dvc subs hooked up to 4 ohm each you get 4x4/4+4 which would be 2 Ohms altogether. But you probably already know this.

[primer]

With DVC 2 ohm, you series the coils on each sub making each sub 4 ohms. Then parallel the 2 subs to the amp making a final load of 2 ohms.

Yeah i finally figured that out. Also i figured out that to figure out the ohms you just do{ (ohm x ohm) / (ohm+ohm) }

So with the two 2 ohm dvc subs hooked up to 4 ohm each you get 4x4/4+4 which would be 2 Ohms altogether. But you probably already know this.

You both said the same thing, just in different ways.

[bkolfo4]

The proper formula for resistance in parallel is:

1/R + 1/R + . . . + 1/R = 1/R (total)

1/4 + 1/4 = 2/4 = 1/2

R (total) = 2

Your formula would not work with (3) 4 ohm subs:

(4x4x4)/(4+4+4) = 5.3 is incorrect

It really is:

1/4 + 1/4 + 1/4 = 3/4 = 1/1.33

R (total) = 1.33

[Joe X]

And here's a way to easily calculate the above:

http://www.1728.org/resistrs.htm

[kjstoken360]

The proper formula for resistance in parallel is:

1/R + 1/R + . . . + 1/R = 1/R (total)

1/4 + 1/4 = 2/4 = 1/2

R (total) = 2

Your formula would not work with (3) 4 ohm subs:

(4x4x4)/(4+4+4) = 5.3 is incorrect

It really is:

1/4 + 1/4 + 1/4 = 3/4 = 1/1.33

R (total) = 1.33

I am new to the subwoofer/car audio thing. I just saw that formula and thought it was right. Thanks for the new formula.