It's Me Posted February 27, 2014 Report Share Posted February 27, 2014 Hello Once Again Sub up,port back Ill be using 3/4 MDF Outside dimensions will be 35Lx17.5Hx18W=11025 square inches,so that would make my inside dinensions 33.5Lx16Hx16.5W=8844 square inches,My sub displacement is .11cf which is 190.08 square inches,My vent will be 64 square inches(4''x16''19''Long) So that would make my vent displacement=1444 square inches,So sub/vent displacement=1634.08 square inches,So I would subtract 1634.08 from 8844,which is 7209.92 square inches,divide 1728 square inches ,which would come to 4.17 cubic feet. Did I do this rite? Thanks Im cutting today Link to comment Share on other sites More sharing options...
Joe X Posted February 27, 2014 Report Share Posted February 27, 2014 Your box is 3.773 cubic feet net tuned to 40.7 Hz, I am assuming you are doing a port to the side (see figure below), it looks that is a for a 15" subwoofer but the 0.11 cubic feet is pretty low for a 15", your tuning is real high so it's very hard to expect that you will play low tuned music any good. Link to comment Share on other sites More sharing options...
It's Me Posted February 27, 2014 Author Report Share Posted February 27, 2014 How many more inches in lenght should i add for 4cf net. yes its fro a 15" sub. 4cf with 19'' long port should be around 35hz,is what the soundqubed guy said Link to comment Share on other sites More sharing options...
Joe X Posted February 28, 2014 Report Share Posted February 28, 2014 Made something around your original dimensions that is 4 cubes, 35Hz and 64 sq" of port area: Link to comment Share on other sites More sharing options...
_paralyzed_ Posted February 28, 2014 Report Share Posted February 28, 2014 One dimension multiplied by one dimension = square inches. One dimension multiplied by one dimension multiplied by one dimension = cubic inches. We deal in cubic inches when referring to volume. Square inches is for area. Link to comment Share on other sites More sharing options...
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