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There are ample calculators online to use, but can anyone explain how to get to the final numbers? Example what are your final ohm loada for 2 Dual 1.4ohm subs? Break or down and explain how you would calculate wiring series then parallel, parallel then parallel that etc? I searched online and on this forum and I know I have seen it in the past, but couldn't find it again. I think it would be super useful for people trying to understand how to wire subs not on those calculators i.e dvc 1.4, dvc 0.7, dvc 0.35.

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Calculations can be greatly simplified if we assume all subs in the circuit have the same final impedance:


Subs in parallel: total impedance = individual sub impedance / number of subs (1)

Subs in series: total impedance = individual sub impedance x number of subs (2)


For hybrid circuits such as series-parallel and assuming all groups(sub circuits) in the circuit have the

same impedance:


groups in parallel: total impedance = individual group impedance / number of groups  (3)

groups in series: total impedance = individual group impedance x number of groups  (4)


To determine the final impedance of dual coil subs (simplest case):


Coils in parallel: sub final impedance = individual coil impedance / 2  (5)

Coils in series: sub final impedance = individual coil impedance x 2  (6)

 

Example: We want to wire 6 JL Audio 13W7 Dual 1.5 ohm coils to a 2 ohm stable amp:


So using formula (6) we get final impedance of each sub with coils wired in series:
sub final impedance = 1.5 x 2 = 3 ohm


Then we use formula (1) to get impedance for 3 subs wired in parallel:
group final impedance = 3/3 = 1 ohm


Then we use formula (4) to get impedance of 2 groups of 3 subs wired in parallel which will be connected in series:
Impedance as presented to the amp = 1 x 2 = 2 ohm

 

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