Aero Ports

[andym85]

to clarify:

to find area: pi*r^2 (or pi*r*r)

to find volume (displacement): pi*r^2*h (or pi*r*r*h)...h=length of the port

example: one 6" port that is 10" long

area=3.14*3^2

area=28.26sq"

volume(displacement) =3.14*3^2*10

volume(displacement)=282.6cubic"

volume(displacement) in terms of cubic feet = 282.6/1728 = .1635cft

[andym85]

more clarification..lol

here is a pic. the red is port area, the blue is volume (displacement). now SURFACE AREA would be the actual physical surface of the black tubing that u can touch, but that is not volume or displacement, displacement is the volume of the air inside of the tube!

[emperorjj1]

i think everyone here is looking for the volume of the port... for tuning

[andym85]

ok ok...i think we are all talking about the same thing. volume is for displacement, but it is also in the equation to figure tuning (the one that i use anyways) and i think that is where we are all gettin confused with each other. here is the equation i use (it looks a lot more complicated than it really is, especially if u arent good at math)

Fb = .159*((Av(1.84*10^8)/(Vb(Lv+.823*Av^.5))^.5

Fb = tuning frequency

Av = vent area

Vb = net volume in cubic inches

Lv = effective length of vent

effective length = physical length + end correction <---1/2 of the ports width

so u need both the port area and the port volume for this equation, but NOT the surface area.

any help?

oh, and in the equation when u see ^.5, that is just another way of saying the square root...that is how u have to do it in excel though.

Edited July 9, 2007 by amatt85

[babyjoker]

since this on topic, how many aero's would ya recommend, (for both 4'' and 6''), for an 18'' ssd?

Edited July 9, 2007 by babyjoker

[andym85]

i would say at least two 4" or one 6"...maybe more..