Aero Ports

[thegr8cody]

how do u measure the square inches of aero ports i need around 240 square inches of port

[andym85]

pi*r^2

pi=3.14

r=radius of port

example: a 4 inch areo, radius of 2"

3.14*2^2=12.56sq" of area

lol...so 19.1 4"aeros or 8.49 6" aeros...dont think that is gonna happen...

[emperorjj1]

thats confusing

[Derrick824]

Aeroports don't work the same way a slot port does. You don't need as much port area with aeros.

[thegr8cody]

so pi means? u do port radius x the depth of the flare?

[Derrick824]

so pi means? u do port radius x the depth of the flare?

pi = 3.14. Think back to geometry & algebra in highschool. amatt85 did a good job explaining it already. Radius = half of the diameter. 4" port = 2" radius, 6" port = 3" radius.

For a 6" port its 3.14*(3*3)=28.26

For a 4" port its 3.14*(2*2)=12.56

When you multiply that by the depth thats calculating for volume. Thats how you'll figure displacement of the ports. For a 6" port thats 10" long 28.26*10=282.6in or 0.16ft.

I hope this helps cause I really don't know any easier way to explain it.

[andym85]

^^yep..pi is just a constant number, kinda like a mile is a constant number...a mile is 5280ft. and pi is 3.14159...(i dont think scientist have actually found an ending decimal place yet, it just goes out to infinity, never repeating)...

[thegr8cody]

alright so say i have a 10 inch pipe,radius is 5",soi say 5 x5 = 25 x 3.14 =78.5 then my depth for 32 hz tuning is 5.35 so do i times 78.5 x the 5.35 that comes out to 419 square inches of port area?

[andym85]

no. your port area is 78.5sq" and your port displacement (or volume) would be 419cubic".

area is a two dimentional measurement. volume is a three dimensional measurement (the third dimension being depth)...hope that clears it up!

[thegr8cody]

well if i need 220 square inches of port vented how many would i need in aero port if i used pvc and shaved the end would that be just as good