OrionStang Posted January 3, 2012 Report Posted January 3, 2012 What kind of vehicle is this going in? Quote SMD Super Seller My Feedback Thread
ChevyBoy95 Posted January 3, 2012 Report Posted January 3, 2012 after all displacements i would look to go around 3-4 cubes. Quote Best Score to Date : 160.5 dB Outlaw (47Hz)[4 XM 15's & 2 Taramps Bass 12k's] BL : http://www.stevemeadedesigns.com/board/topic/147800-chevyboy95s-4-15s-7krms-wall-1533-db-on-half-power/YouTube: http://www.youtube.com/hitemwiththeflex/
fmedina Posted January 3, 2012 Report Posted January 3, 2012 after all displacements i would look to go around 3-4 cubes. yes. and with the amp hes using at 2ohms id go to as close as possible to 4cuft lol Quote
lagexe Posted January 4, 2012 Author Report Posted January 4, 2012 the net volume after all displacements would be about 3.8 if i did it right. but the port area is a lil small. if you want some help on a box design shoot me a pm. Also, I guess I'm not figuring the volume right I still get around 6cf Am I suppose to just figure the volume for the chamber or the whole sub. Or perhaps I'm just doing it wrong period(.)? 2' 5" = 29" 2' 6" = 30" 1' 1" = 13" 29" * 30" * 13" = 11310" ----- BACK TO CUBES OF FEET ----- 12"x12"x12" = 1728" 11310/1728 = 6' 5" (to the 3rd) It's been years since I've had to do area or volume, so I could very well be wrong. If so, what is the formula again? Quote
lagexe Posted January 4, 2012 Author Report Posted January 4, 2012 What kind of vehicle is this going in? 1994 Jeep Grand Cherokee Laredo Quote
OrionStang Posted January 4, 2012 Report Posted January 4, 2012 Your math looks right, but you aren't taking the thickness of the wood into consideration. Quote SMD Super Seller My Feedback Thread
fmedina Posted January 4, 2012 Report Posted January 4, 2012 (edited) the net volume after all displacements would be about 3.8 if i did it right. but the port area is a lil small. if you want some help on a box design shoot me a pm. Also, I guess I'm not figuring the volume right I still get around 6cf Am I suppose to just figure the volume for the chamber or the whole sub. Or perhaps I'm just doing it wrong period(.)? 2' 5" = 29" 2' 6" = 30" 1' 1" = 13" 29" * 30" * 13" = 11310" ----- BACK TO CUBES OF FEET ----- 12"x12"x12" = 1728" 11310/1728 = 6' 5" (to the 3rd) It's been years since I've had to do area or volume, so I could very well be wrong. If so, what is the formula again? find the gross volume then subtract the sub, port, bracing(if any), etc. displacement from it and you get the net volume. use torres calc it helps a lot Edited January 4, 2012 by fmedina Quote
lagexe Posted January 4, 2012 Author Report Posted January 4, 2012 Your math looks right, but you aren't taking the thickness of the wood into consideration. Oh... that makes sense... However, I'm just gonna take ya'lls word that is 3-4cf. I'm not sure how to take all the wood side and the thickness into consideration. Quote
TeamHT Posted January 4, 2012 Report Posted January 4, 2012 I would do just a wee bit smaller for the SSD. I would like at like 2.75^3 after displacement with about 14^2 of port per cube Quote Tell me...does this smell like chloroform to you?
lagexe Posted January 4, 2012 Author Report Posted January 4, 2012 I would do just a wee bit smaller for the SSD. I would like at like 2.75^3 after displacement with about 14^2 of port per cube What would that before displacements? Above 3cf? If not, why would It be good to go below recommended cubes? Quote
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