MaxVolume Posted November 27, 2014 Report Share Posted November 27, 2014 pi x r x r gives area of a circle to calculate PORT area, you'd find the circumference of the circle (2 x r) and multiply the result by port length yeah science What? Masterbasser had it right. Circumference x length = inside surface area of the port, not useful for what we are doing. And 2 x R is diameter, not circumference. doh! forgot the pi in my circumference equation, and now see that you're comparing square ports to aero ones Link to comment Share on other sites More sharing options...
Masterbasser Posted November 27, 2014 Author Report Share Posted November 27, 2014 the speaker im lookin at calls for 40 square inches of port at 10 inches in length for a tune around 34 hertz, street bass setup. does that seem right for an 18? i have been told by some friends that 10 inches for a port is way to short but thats what it is calling for on the spec sheet i have here Kenwood excelon ddx795 3 370 amp CES alternators (audio side only) McLaren dome tweeters Crescendo 6.5 ultra neos NVX JAD800.4 4 PA x4 SPL 18's 4 Digital Designs m5's at .7 ohms each 2 K2 80 ah lithiums 3 group 31 agms Ledglow million color (12 piece) 2007 Yukon xl Link to comment Share on other sites More sharing options...
Joe X Posted November 27, 2014 Report Share Posted November 27, 2014 Can you tell what sub is it? maybe post the spec sheet? Link to comment Share on other sites More sharing options...
Masterbasser Posted November 27, 2014 Author Report Share Posted November 27, 2014 dont really want to post any brand want to keep it on the downlow for now this is exactly what it says word for word though All displacements for port and driver already figured. All power measurements are for port noise on ported enclosure and cone displacement on sealed enclosure. SB= street bass Spl=competition Ported- 6.0 ft3 40 Square inches of port X 10 inches in length 32 hertz at 5000 watts SB Ported- 6.0 ft3 120 square inches of port X 1 inches in length 65 hertz 5000 watts SPL Bandpass- rear chamber 3.0 ft3 sealed Front chamber 6.0 ft3 100 square inches of port at 8 inches in length 72 hertz Bandwidth 50-78 hertz 5000 watts SPL i want to go for the ported street bass since all i have is 6 cubic feet for the box Kenwood excelon ddx795 3 370 amp CES alternators (audio side only) McLaren dome tweeters Crescendo 6.5 ultra neos NVX JAD800.4 4 PA x4 SPL 18's 4 Digital Designs m5's at .7 ohms each 2 K2 80 ah lithiums 3 group 31 agms Ledglow million color (12 piece) 2007 Yukon xl Link to comment Share on other sites More sharing options...
Masterbasser Posted November 27, 2014 Author Report Share Posted November 27, 2014 joe x i was going to send you a pm but it says you cant receive messages Kenwood excelon ddx795 3 370 amp CES alternators (audio side only) McLaren dome tweeters Crescendo 6.5 ultra neos NVX JAD800.4 4 PA x4 SPL 18's 4 Digital Designs m5's at .7 ohms each 2 K2 80 ah lithiums 3 group 31 agms Ledglow million color (12 piece) 2007 Yukon xl Link to comment Share on other sites More sharing options...
Triticum Agricolam Posted November 27, 2014 Report Share Posted November 27, 2014 Unfortunately the box specs don't really help us. I can tell you that 40 sq in of port area seams really small for an 18" but without the specs on the subs I can't tell you what would be an appropriate amount. If you want us to help you, you need to give us the specs on your sub. "Nothing prevents people from knowing the truth more than the belief they already know it.""Making bass is easy, making music is the hard part."Builds: Link to comment Share on other sites More sharing options...
Masterbasser Posted November 27, 2014 Author Report Share Posted November 27, 2014 think the enclosure specs are garbage, no real parameters since subs are built to custom order, at least not yet prolly just build to 18" dd9518 enclosure specs, 100s q inch port length around 26 inches of port Kenwood excelon ddx795 3 370 amp CES alternators (audio side only) McLaren dome tweeters Crescendo 6.5 ultra neos NVX JAD800.4 4 PA x4 SPL 18's 4 Digital Designs m5's at .7 ohms each 2 K2 80 ah lithiums 3 group 31 agms Ledglow million color (12 piece) 2007 Yukon xl Link to comment Share on other sites More sharing options...
MrSkippyJ Posted November 27, 2014 Report Share Posted November 27, 2014 pi x r x r gives area of a circle to calculate PORT area, you'd find the circumference of the circle (2 x r x pi) and multiply the result by port length yeah science multiplying by the length gives you port volume, not area. F150: Stock 2019 Harley Road Glide: Amp: TM400Xad - 4 channel 400 watt Processor: DSR1 Fairing (Front) 6.5s -MMats PA601cx Lid (Rear) 6x9s - TMS69 Link to comment Share on other sites More sharing options...
MaxVolume Posted November 27, 2014 Report Share Posted November 27, 2014 multiplying the area of the opening by the length would give port volume multiplying circumference by length gives interior area of port Link to comment Share on other sites More sharing options...
Masterbasser Posted November 27, 2014 Author Report Share Posted November 27, 2014 trying to under stand why an 18" sub calls for 40 sq inch of port a 10 inch of length does it have soemthing to do with the length of the port being shorter so the air does not become as pressurized going down a long slot/tube so 40 sq inch of port seems like a larger port area to the subwoofer? Kenwood excelon ddx795 3 370 amp CES alternators (audio side only) McLaren dome tweeters Crescendo 6.5 ultra neos NVX JAD800.4 4 PA x4 SPL 18's 4 Digital Designs m5's at .7 ohms each 2 K2 80 ah lithiums 3 group 31 agms Ledglow million color (12 piece) 2007 Yukon xl Link to comment Share on other sites More sharing options...
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