IH8PunkRok Posted May 14, 2008 Report Share Posted May 14, 2008 http://www.the12volt.com/ohm/ohmslaw.asp alright here we go. in the hypothetical calculation of power we resort to the laws created by Ohm (dont remember his first name) my question is simple in equations involving impedance ® wut number would i mathematically enter into the equation? for example when calculating amps i divide volts (E) by impedance ® I=E/R so i want to find amps i know that my system is running 70 volts (theoretical situation) and my impedance is 1 ohm. so does that mean that my amps are also 70? if its 2 ohms does it mean i have 35 amps now? wut about .5 ohm do i now have 140 amps? it seems logical but i want to be sure im doing the calculations correctly Quote -Matt2005 Dodge Magnum RTJVC KD-AVX1 2 PPI S580.2 Obsidian Audio ST1 Horn Tweeters PRV 8MB450s Audio Legion 3500.1D 2 RE MT 18s 360 ah LiFePO4 BatterySHCA 2/0 155.2 @ 29 hzKicker CVR 15's buildDD 3512e buildMini T-Line Build(6) 8s BuildNightshade 15s Wall BuildMagnum AB XFL 12s BuildNewest Magnum Build Link to comment Share on other sites More sharing options...
IH8PunkRok Posted May 15, 2008 Author Report Share Posted May 15, 2008 wut r u guys scared of math or is it a dumb title? Quote -Matt2005 Dodge Magnum RTJVC KD-AVX1 2 PPI S580.2 Obsidian Audio ST1 Horn Tweeters PRV 8MB450s Audio Legion 3500.1D 2 RE MT 18s 360 ah LiFePO4 BatterySHCA 2/0 155.2 @ 29 hzKicker CVR 15's buildDD 3512e buildMini T-Line Build(6) 8s BuildNightshade 15s Wall BuildMagnum AB XFL 12s BuildNewest Magnum Build Link to comment Share on other sites More sharing options...
Stephen Posted May 15, 2008 Report Share Posted May 15, 2008 yes you are right Quote you can cook bacon shirtless if you're not a pussy...lol not hatin, but am i wrong here it looks as if the amp is not grounded its hooked directly to the battery. it that the way it should be. DC POWER Link to comment Share on other sites More sharing options...
mrwigglezdj Posted May 15, 2008 Report Share Posted May 15, 2008 x2 and i havent a first clue as to what you are even looking to learn from that lol... hypothetical calculation of power why not just get a clamp meeter and volt meeter and do real power tests (for a given freq) Quote Americas loudest work van2006 iasca heavyweight bassboxing champion at 150.4 db with 60second average TL8 memphis PR15s,12 memphis PR6.5's coax,4 memphis PR 1inch tweets Link to comment Share on other sites More sharing options...
etaks_crew Posted May 15, 2008 Report Share Posted May 15, 2008 Not afraid of math just not really a big fan of crazy math Quote Link to comment Share on other sites More sharing options...
IH8PunkRok Posted May 15, 2008 Author Report Share Posted May 15, 2008 well see id rather do the math because i love math and im plannin on bein an electrical engineer so im gonna need to know these things Quote -Matt2005 Dodge Magnum RTJVC KD-AVX1 2 PPI S580.2 Obsidian Audio ST1 Horn Tweeters PRV 8MB450s Audio Legion 3500.1D 2 RE MT 18s 360 ah LiFePO4 BatterySHCA 2/0 155.2 @ 29 hzKicker CVR 15's buildDD 3512e buildMini T-Line Build(6) 8s BuildNightshade 15s Wall BuildMagnum AB XFL 12s BuildNewest Magnum Build Link to comment Share on other sites More sharing options...
Stephen Posted May 15, 2008 Report Share Posted May 15, 2008 well see id rather do the math because i love math and im plannin on bein an electrical engineer so im gonna need to know these things im taking a class to be a technician right now and thats one of the basics you will see over and over and then about 6000 more times. Quote you can cook bacon shirtless if you're not a pussy...lol not hatin, but am i wrong here it looks as if the amp is not grounded its hooked directly to the battery. it that the way it should be. DC POWER Link to comment Share on other sites More sharing options...
Decaf Posted May 15, 2008 Report Share Posted May 15, 2008 (edited) http://www.the12volt.com/ohm/ohmslaw.aspalright here we go. in the hypothetical calculation of power we resort to the laws created by Ohm (dont remember his first name) my question is simple in equations involving impedance ® wut number would i mathematically enter into the equation? for example when calculating amps i divide volts (E) by impedance ® I=E/R so i want to find amps i know that my system is running 70 volts (theoretical situation) and my impedance is 1 ohm. so does that mean that my amps are also 70? if its 2 ohms does it mean i have 35 amps now? wut about .5 ohm do i now have 140 amps? it seems logical but i want to be sure im doing the calculations correctly opps didnt read the question u r correct Edited May 15, 2008 by decafcappucino Quote Link to comment Share on other sites More sharing options...
Mosin Posted May 15, 2008 Report Share Posted May 15, 2008 You guys make me wish you guys sat next to me when I was in math class! Quote Derp. Link to comment Share on other sites More sharing options...
moh.vze.com Posted May 15, 2008 Report Share Posted May 15, 2008 im taking a class to be a technician right now and thats one of the basics you will see over and over and then about 6000 more times. Word. Quote DC Audio - Singer Alternators - Knukonceptz - XS Power - Hybrid Audio - Rockford Fosgate - Second Skin Audio - SMD - Sundown Audio - Elemental Designs Link to comment Share on other sites More sharing options...
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