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so im gonna be makin my custom box soon and i just recently thought about this: would i gain a slight advantage if i used 4 8" SQ HDS208's or if i used 2 12" SQ HDS300's? i mean mathematically 4 8"s have more surface area but ive heard that 2 12's hit lower than 4 8's so i dunno. help!

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mathematically 4 8"s have more surface area

that is not correct.

2 12's more cone area

4 x 8 =200.96 square inches of surface area

2 x 12 = 226.08 square inches of surface area

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mathematically 4 8"s have more surface area

that is not correct.

2 12's more cone area

4 x 8 =200.96 square inches of surface area

2 x 12 = 226.08 square inches of surface area

well my "mathematically speaking" never really included "logically speaking". 2 12's it is

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i like 8s more then 12s..but i like 15s more then 8s.

why not 6 8s?

or 4 8s in a forth?

jvc deck

stinger 1800 front

hc 2000 kinetic rear

2 runs of 1/0g

big 3/4

ct 60.4

2 ct 1400.1

ct EXO 15 d1

lots of deadner

type r comps front stage

6 kicker tweets rear stage

lots of great stuff

coming soon

ho alt

more bats

ct comps for front stage

more deadner

sweet amp rack

lots of L.E.D lights

new deck (thinking 80 prs, or flip out)

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