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Infinitely variable ohm load. Is box rise obsolete?


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Through ohms law, you would get higher voltage and current on the output side, and an exponential increase in current on the input side, but voltage would remain the same

Impossible. You cannot raise voltage AND current without more power.

Are you trying to say you would have to have a greater input voltage on the input to achieve what SnowDrifter is talking about? The only thing that is holding the output of the amp back is the impedance rise from the subwoofer box, if you diminish that you will have more output from the amp without needing an excess of voltage. The power is already there, you just need to unlock it.

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Through ohms law, you would get higher voltage and current on the output side, and an exponential increase in current on the input side, but voltage would remain the same

Impossible. You cannot raise voltage AND current without more power.

Exactly!!! That's what I'm saying. Raise voltage and in turn, current on the output side. That would then increase draw on the input side at an exponential rate. Same voltage, more current IS more power. I'm not saying you create power from scratch. I'm saying you create an environment in which the amp can put out the post power it can by compensating for box rise

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Through ohms law, you would get higher voltage and current on the output side, and an exponential increase in current on the input side, but voltage would remain the same

Impossible. You cannot raise voltage AND current without more power.

Exactly!!! That's what I'm saying. Raise voltage and in turn, current on the output side. That would then increase draw on the input side at an exponential rate. Same voltage, more current IS more power. I'm not saying you create power from scratch. I'm saying you create an environment in which the amp can put out the post power it can by compensating for box rise

Put your flame suit on, ignore the doubters, and test the theory. Just be careful, high voltage/current aint' no joke.

The funny part is, if this works, everybody will be jumping at it saying it was an awesome idea and what a genius you are. If it blows up, everyone will line up to tell you how stupid you were for trying it in the first place.

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Just throwing it out there..... I got a lot of hate for doing caps before they took off. Now they are the new fad hahaha

Who knows... Maybe I'll find something new. Maybe I won't. Either way it's fun to toy with

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Interesting. not sure if or how it will work but i will be looking forward to finding out.

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Through ohms law, you would get higher voltage and current on the output side, and an exponential increase in current on the input side, but voltage would remain the same

Impossible. You cannot raise voltage AND current without more power.

Exactly!!! That's what I'm saying. Raise voltage and in turn, current on the output side. That would then increase draw on the input side at an exponential rate. Same voltage, more current IS more power. I'm not saying you create power from scratch. I'm saying you create an environment in which the amp can put out the post power it can by compensating for box rise

So you mean instead of just wiring down coils to a lower impedance to rise up to your desired level you add more inefficiency into the system to match impedance?

A transformer will not just pick a magic number and set your amp to "see" that impedance. It will load the input coil with some fraction or multiple of the load on the output coil (depending on number of turns per side). So while you could theoretically halve the impedance your amps sees with a transformer you'll lose 3-8% efficiency through losses unless you have some sort of superconductor or super-magnetic material AND your amp will still see below safe impedance when the impedance of the loudspeaker drops.

Furthermore you have the even greater risk that if you open a coil or a speaker wire becomes disconnected, the input coil will not be loaded and your amp will then see a dead short.

I'm going to go out on a limb and say this is a terrible idea BEFORE you try it.

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You're going to have losses through a variac. By that I mean flux losses and whatnot since there is no such thing is a 100% efficient transformer. And really efficient ones are expensive. I would venture to guess that it would work, but might be more trouble than it's worth.

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The load the speaker shows the amp is the load the speaker shows the amp. No amount of manipulation of the power going to it will change the load. What you're trying to do is downstream of that.

That's what I'm saying based on my knowledge, but I'm no EE and I never considered this before.

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The load the speaker shows the amp is the load the speaker shows the amp. No amount of manipulation of the power going to it will change the load. What you're trying to do is downstream of that.

That's what I'm saying based on my knowledge, but I'm no EE and I never considered this before.

I guess we'll have to see ;)

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What is downstream in an AC circuit?

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I would have replied earlier, but I was measuring the output of my amp with a yardstick . . .

What you hear is not the air pressure variation in itself

but what has drawn your attention

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An acoustic event has dimensions of Time, Tone, Loudness and Space

Everyone learns to render the 3-dimensional localization of sound based on the individual shape of their ears,

thus no formula can achieve a definite effect for every listener.

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